Not so fast.
There’s more to cables than just how many wires are connected.
I finished my dissection. And yes,
I can confirm that all 8 wires are soldered to pins. And that’s a good thing.
Here’s how they soldered the pins:
- (2) yellow (“gold”) conductors to L+
- (2) yellow (“gold”) conductors to R+
- (4) black conductors to shared gnd
Here’s the photos to prove it:
So if the ground terminal on the 3.5mm plug has FOUR wires soldered to it, why is the resistance DOUBLE on the ground terminal as compared to the + terminals?
Clearly, the huge resistance/impedance disparity isn’t caused by ‘fake wires’ not being soldered, because all 8 wires are soldered to terminals.
So what’s causing it?
Well, upon closer inspection, I determined it is being caused by:
1. Using 2 drastically different wire gauges
2. The
way the wires are soldered (ie the configuration of what wires go to what terminals)
For #1 above, despite the black and gold wires having roughly similar external diameters (ie the insulation), the
size (gauge) of the internal conductors is vastly different.
Once the insulation layer is stripped away, it’s readily apparent that the gold conductors are
many times thicker. In other words, the actual gauge of the black wire’s copper conductors are ridiculously thin and tiny, and the actual gauge of the gold wire’s copper conductors are super thick in comparison.
Look at the difference side by side (2 different photos of the same cable, shot in different light):
So that brings us to #2 in my list above. This copper conductor’s size difference was compounded by the
configuration of which wires were soldered to which terminals.
As I stated earlier, they soldered them this way:
- (2) yellow (“gold”) conductors to L+
- (2) yellow (“gold”) conductors to R+
- (4) black conductors to shared gnd
But because the black wires are so paper thin compared to the gold wires, the black wires have a very high resistance (and thus impedance) and the thick gold wires have a much lower resistance (and thus impedance).
Thin gauge conductors = high resistance, thick gauge conductors = low resistance.
How they
should have soldered them IMO, was to better balance out the differences in resistance. Maybe like this way:
- (1) yellow (“gold”) and (2) black conductor to L+
- (1) yellow (“gold”) and (2) black conductor to R+
- (2) yellow (“gold”) conductors to shared gnd
Or, if the cable had a balanced TRRS configuration, they could have soldered them this way:
- (1) yellow (“gold”) and (1) black conductor to L+
- (1) yellow (“gold”) and (1) black conductor to L-
- (1) yellow (“gold”) and (1) black conductor to R+
- (1) yellow (“gold”) and (1) black conductor to R-
If they had done this, the resistance of the whole cable would have been even and not so lobsided.
Even better, they really should have used 8 wires that all had the same internal conductor size (gauge). Not 4 wires super heavy gauge and 4 wires paper thin gauge.
I plan on putting all new ends on my cable, and at that time I will use the opportunity to reconfigure which wires are soldered to which pins, so that the resistance will be even across all of the pins.
Now, with all that said, is this a ‘bad’ cable? No, it’s not a terrible cable. It is technically a ‘
functional’ cable. It looks nice, has all 8 pins soldered, has a nice plug, a chin slider, and is softer and more flexible than the previous cable.
But is it a ‘good’ cable? Well, using 2 drastically different thicknesses of wire, and soldering them in such a way that the ground pins have
double the resistance of the + pins shows a concerning level of technical understanding and cable building ability.
There are certainly
worse cables out there. But there are certainly other cables (at the same price) that have all wires soldered
AND have well-balanced cable resistance between all of the pins.
So I’ll let you decide for yourself if you’re happy buying this new tiger cable. I can’t make that decision for you. All I can do is dissect them, present the facts, and show what goes on ‘under the hood’ of these cables.