Helmore
100+ Head-Fier
- Joined
- Nov 15, 2009
- Posts
- 227
- Likes
- 10
Quote:
I don't think your calculations are correct. In the first place, I don't think there is any use in doing DC power calculations when it comes to headphones and amplifiers and your power calculations are a bit wrong (the amp can't create a 38 V potential difference). Keep in mind, we're talking about a single ended β22.
The specifications page on amb.org states that the β22 can supply 43 Vpp unloaded. Because we are talking about a 600 Ohm load, let's just say it can supply 42 Vpp to make it easier. That mean it has an amplitude of 21 V, which would translate to sqrt(1/2)*21= 14,85 Vrms. From that you can calculate its power output into a T1.
Prms = (14,85)^2 / 600 = 367,5 Wrms
That's still eardrum shattering volumes, but your 2,5 Watts is simply wrong.
P.S. For a balanced β22 you just have to double that power figure.
Oh, and I can also be wrong.
Originally Posted by b0dhi /img/forum/go_quote.gif Bizkid, go to The β22 Stereo Amplifier and go to "Specifications". Where it says "Maximum output voltage at 1KHz, prior to onset of clipping" gives an idea of how the amp performs into various loads. In this case we can assume that the amp will be able to drive at least 38Vpp into 600ohm since it can do so for 300ohms. Using Power = Voltage^2/Resistance = 38Vpp^2/600 = at least 2.4W into 600 ohms. If you know the measurement was done with a sine wave (it usually is), you can roughly convert Vrms to V by dividing by 0.3535. By the way, the assumption regarding drive voltage only applies to easier loads. You can't say that it can drive 40Vpp into 600 ohms, then assume it can drive 40Vpp into 8 ohms. Also things change when you start dealing with different types of amps, like electrostats, since capacitance and complex impedance comes into play. |
I don't think your calculations are correct. In the first place, I don't think there is any use in doing DC power calculations when it comes to headphones and amplifiers and your power calculations are a bit wrong (the amp can't create a 38 V potential difference). Keep in mind, we're talking about a single ended β22.
The specifications page on amb.org states that the β22 can supply 43 Vpp unloaded. Because we are talking about a 600 Ohm load, let's just say it can supply 42 Vpp to make it easier. That mean it has an amplitude of 21 V, which would translate to sqrt(1/2)*21= 14,85 Vrms. From that you can calculate its power output into a T1.
Prms = (14,85)^2 / 600 = 367,5 Wrms
That's still eardrum shattering volumes, but your 2,5 Watts is simply wrong.
P.S. For a balanced β22 you just have to double that power figure.
Oh, and I can also be wrong.