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Originally Posted by upstateguy /img/forum/go_quote.gif
- I wonder if you could go into some detail as to what kind of damage a capless LOD might do because this has become a little confusing?
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First of, to under stand the underlying danger of caped vs. cap-less, you need to understand that music is in AC form (that is what caused the electric coil to vibrate in an magnetic field, as DC will just push the coil to one side). However, almost all output from a DAC chip has some DC offset (on top of the AC signal). If this DC voltage is small enough, it will push the coil in one side while the AC signal can still be turned into music. If the voltage is too large, it will either knocks the coil out of alignment (bad!) or heat up and damage the coil (extremely bad!).
In typical design, a RC circuit (R = resistor; C = capacitor) is included just before the output to filter out any DC voltage. However, since Sandisk decides to left out the RC circuit for the line-out, the DC voltage (1.4V in fuze's case) will make it way to any downstream component that doesn't have an input cap to protect itself (*though not confirmed, I think it is Sandisk's idea to implement the RC circuit on the accessories side, just to save space on the player motherboard). If the DC makes it way to the amp, the amp will amplify the DC by whatever gain the amp is on, then send the mixture of AC and DC to the headphone. i.e. Amp with gain of 2 will output 1.4V x 2 = 2.8V DC. If the DC voltage is large enough and the headphone is incapable of handling it, damage will occur.
Quote:
Originally Posted by upstateguy /img/forum/go_quote.gif
- How can do you determine if its safe to use a capless LOD with your rig?
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If you know your amp has input or output caps, then it is safe to use a capless LOD.
A fast and easy way to determine whether the amp has in/output cap or not is to connect the amp and Fuze with a capless LOD, plays music and turns the amp up (around half the volume should be enough) then measures the amp's output left/right channels against the ground via a voltmeter. If there are caps, it will be zero volt (in real practice, there will be a very tiny voltage, much much less then 1V presents most of the time, like 0.001V). If you detects DC voltage on the amp's output, then the amp doesn't have any cap.
Quote:
Originally Posted by upstateguy /img/forum/go_quote.gif
- Do you feel, that in general, if you're not sure of the circuitry in your amp, it's probably better to be on the safe side, as Woody posted, and not use a capless LOD?
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Yes.
As explained before, it is technically better not to put two caps in series; but if you are not sure, then you should always choose to use a cap'ed LOD just to be safe.
Quote:
Originally Posted by upstateguy /img/forum/go_quote.gif
- What kind of damage can occur if the resistor is left out of the dock?
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In the RC circuit, it is the capacitor that actually does the filtering (as DC can not pass through cap, only AC can). The resistor is there to serve mainly two functions: 1) to behave as a stunt, allowing any DC leakage to bleed to the ground so it won't go to the amp/headphone. 2) to lower the overall impedance so the problem of dielectric absorption can be minimized (= minimizing the noise caused by the cap itself). I am not an EE so I won't try to go into any detail, but there is a paper by Walter G. Jung and Richard Marsh called "Picking Capacitors" that has all the detail.
To focus back to the 1st function, there are generally several situations where resistor can be useful:
One, when the caps is faulty and allows DC voltage to leak through. This is rare but it can happen as the cap aged. The best way to determine whether the is a leakage is by regular check up via a voltmeter. There should not be any DC voltage on the LOD output. Also, every cap has its own rated lifespan (usually from 1000hrs up to ten of thousands). So reusing old cap poses higher possibility for caps' failure. In situation like this, resistor help to bleed away some of the voltage, but it isn't 100% safe and the cap should be replaced right away.
Two, it takes time to charge up a cap before it can filter the DC. The larger (capacitance wise) the cap, the more time it needs. Before the cap is charged up, a small amount of DC will leak. A small value resistor helps to bleed this voltage away. However, if the capacitance isn't very big, then it will charge up fairly quick and the danger that DC leakage posed is minimum. In the worst case scenario where a big surge does happen, there is no guarantee that the headphone will survive even if there is stunt resistor in place. This is why a good practice for any amp user is, you should turn the source's power up first ,follow by the amp (always in minimum volume)
before plug in your headphone into the amp. This will help reduce the chance that a surge coming from the source or the amp from damaging your headphone. If you follow the right way of connecting and turning on/off your rig, your headphone will be safe.
So, the resistor can be omitted if 1) the cap isn't faulty (using a good quality cap helps), 2) follow the right on/off procedure and 3) can't hear any difference b/w resistors / no-resistors.
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Originally Posted by upstateguy /img/forum/go_quote.gif
- And finally, is there some way to tell/measure if the proper resistor is there before using a LOD purchased on ebay, for instance?
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Not to my knowledge.
Again, I am not an EE but those above are to the best of my knowledge. If anyone find error in it, please point it out. Thanks.