NewAKGGuy
100+ Head-Fier
- Joined
- Jun 18, 2009
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Quote:
That's not the part I reponded to. It was this "Amplifiers (including small ones in portable devices) have no problem providing the required voltage. Their limitation is current. If your amplifier isn't capable of providing enough current, the voltage sags, compromising the sound. Because this happens preferentially at certain frequencies, this affects your frequency response." Either you don't understand what you said here or specifically chose to ignore it and it's completely wrong and contradicts the running out of voltage for high impedances.
Actually, I think this part of Jim's response is correct. It's definitely the case for Home-Fi. I'm not an electrical engineer, nor am I a physicist, but I did work in the high-end audio business for many years and in that time I never saw an 8 or 16ohm rated speaker that was a real challenge for just about any off the shelf El Cheapo receiver to drive. Conversely if you wanted to drive large planar speakers with 4 and 2 ohm impedance ratings, and impedance curves that dipped down to .5 ohms at some frequencies (read Martin Logan Sequel II etc), that's when you needed the massive Krells, Spectrals, and Mark Levinsons that could drive the required voltages into a (virtual) dead short. It was our understanding (albeit propagated by the amp manufacturers) that wattage output is a function of both current and voltage and that it's relatively easy and cheap to build an amplifier that achieves a high wattage output but with little ability to deliver current, but much more difficult and expensive to build an amplifier that delivers high wattage and current. In my experience, if you have two speakers with the same efficiency rating, it requires a sturdier and more thoroughly built amplifier to drive the lower impedance speakers than it does the higher impedance speakers, and consequently I would assume that lower impedance speakers are more difficult to dive, holding efficiency equal.