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Originally Posted by Jeff Guidry /img/forum/go_quote.gif
Of course I see now thanks. However, if a cone must move faster at a 1w signal at a given frequency than a 0.1w signal at the same frequency, wouldn't that have an effect on the frequency being produced? It would seem that because a high amplitude signal moves cones faster it would cause the resulting sound to be of higher frequency, and that would have to be compensated for in some way.
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The frequency is dependent on the periodicity of the cone's movement, not the speed at which it moves.
In other words, the time it takes for the cone to complete one cycle.
For example, one cycle of 1,000 Hz is 1/1,000 or 0.001 seconds.
So as long as the cone is completing one cycle every 0.001 second, it will be outputting 1,000 Hz, regardless of what its excursion is and subsequently what its speed is.
However...
Speed CAN alter frequency in one respect. And that's Doppler shifting.
Say you've got the speaker reproducing 100 Hz and 1,000 Hz. Of course there will be more cycles of 1,000 Hz occurring during that 100 Hz period. And because the same cone that's reproducing the 100 Hz is reproducing 1,000 Hz, the 1,000 Hz signal can become Doppler shifted.
As the cone is moving toward you, it will compress the 1,000 Hz waves causing them to be higher in frequency. As the cone is moving away from you, it will stretch out the 1,000 Hz waves causing them to be lower in frequency.
This is the same effect that causes a car's horn to sound higher in pitch while the car is heading toward you and lower in pitch as it passes you and moves away from you.
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Again, I am just an average guy with no physics background so I have no idea what I am talking about, just trying to wrap my head around this. |
No problem!
I once had to wrap my head around the same thing too (not like anyone comes out of the womb knowing this stuff). So I asked questions, same as you are.
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