TheSloth
Headphoneus Supremus
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- Aug 3, 2005
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Quote:
Thank you for the clarification. The relevance here is that in terms of the output stage of the module, it makes no difference to the amount of current supplied whether it is a balanced setup or not, and therefore the improvement from the new output stage will be common to both single ended and balanced drive schemes. In a balanced drive scheme, the imedance is halved, however the current output of each module remains unchanged.
Originally Posted by jcx At the same power P Balanced Drive amplfiers have to supply the full current I from both amplifiers at the same time to compare we want the same power P into a given load R P = I * V, I = V / R To get a given P a single ended amp is putting out current I amperes and V volts In a Balanced Drive amp there are 2 amplifiers , each putting out ½ V (+ and -) for a total drive voltage difference across the load of ½ V – (- ½ V) = V with V volts across load R the current drawn is V / R = I which is the same current the single ended amplifier has to supply In Balanced Drive each amplifier has to still supply the full I even though they only swing ½ V each Because the operating point of each amplifier side of the Balanced Drive has to supply the full I for only ½ V we say the load on each amplifier looks like the impedance (resistance) is lower by ½ = a 2x “heavier” load Balanced drive doubles the possible voltage swing, but to achieve the potential 2x V the amplifiers on each side would have to supply 2x I |
Thank you for the clarification. The relevance here is that in terms of the output stage of the module, it makes no difference to the amount of current supplied whether it is a balanced setup or not, and therefore the improvement from the new output stage will be common to both single ended and balanced drive schemes. In a balanced drive scheme, the imedance is halved, however the current output of each module remains unchanged.