artizen65
Head-Fier
IMHO Ferbose has made the most sense so far.
mofonyx what you have been working with is the rated output of the amp not the actual current that the amp draws from the wall. P=I^2 * R where P is the output power of the amp into a nominal speaker load. Say in this case R = 8 ohms. So if the output power of the amp is 100 watts P = 100.
100 = I^2 * 8
100/8 = I^2
12.5 = I^2
Square root of 12.5 = I
3.535 = I
So roughly 3.5 amps are being output from the amplifier at 100 watts into an 8 ohm load.
Ok now is where my time out of the field gets a little fuzzy. You must draw in as much current as you output. Now the input power supply will consume approximatly 80 to 100 % of the output power. So you must draw approximatly 7 amps from the wall to output 3.5 amps into an 8 ohm load.
It does get alot more complicated than this but this is a start.
mofonyx what you have been working with is the rated output of the amp not the actual current that the amp draws from the wall. P=I^2 * R where P is the output power of the amp into a nominal speaker load. Say in this case R = 8 ohms. So if the output power of the amp is 100 watts P = 100.
100 = I^2 * 8
100/8 = I^2
12.5 = I^2
Square root of 12.5 = I
3.535 = I
So roughly 3.5 amps are being output from the amplifier at 100 watts into an 8 ohm load.
Ok now is where my time out of the field gets a little fuzzy. You must draw in as much current as you output. Now the input power supply will consume approximatly 80 to 100 % of the output power. So you must draw approximatly 7 amps from the wall to output 3.5 amps into an 8 ohm load.
It does get alot more complicated than this but this is a start.
