Quote:
Originally Posted by Dr. Strangelove /img/forum/go_quote.gif
Analog interconnects make a big difference because they pass an analog signal. Said analog signal is very fragile as it is a variable voltage, and therefore has an almost infinite amount of states. Because of the almost infinite amount of states, the signal can be effected in an equally infinite amount of ways.
A digital cable makes very little difference: as long as the signal it is passing can be decoded by the receiver (Example here would be LPCM and DAC) then the signal is the same as the source. The voltages might have been rounded off, the amplitude might have been decreased, but it makes no difference because the decoder still knows what it means. The cable only needs to pass two states: maximum voltage, and no voltage. Therefore, it only has two possible states of interference that effect the perceivable outcome: it works or it doesn't work (This is an oversimplification but it does not have bearing on our conclusion).
The only feature of the signal that a better cable will effect is the length you can run the signal before it cuts out.
To quote BlueJeans Cable:
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.5, up or down? .4 up or down? .6 up or down? .499 up or down? .501 up or down? see where I'm going with this?
Your oversimplified version doesn't take into affect dielectric properties.
In optical this is not a problem, but if reflections add jitter, or worse cause the signal to be 70% of the light at a given time, or reflect so 50% arrives at the right time and 50% at a slightly later time then Houston we have a problem. The receiver must make a decision whether it is a 1 or 0.
Your quote from BJC is very accurate, but I think you misunderstood it. It is saying that if a signal arrives, yet it has slight imperfections, but was understood perfectly, than it will sound the same as if it did not have those slight imperfections. It does not say that imperfections can change the sound.
Jitter does not cause huge gaps in time to disappear, it simply causes some of the 44,100 points to be in a different spot by a certain amount. This can manifest itself in more than one way I'd assume. It would effectively be the same affect of misinterpretations on the receiving end for 1s and 0s. It doesn't mean it wont work, but it can cause slight variations in sound. Oversimplifying does not work in this case, because one must consider what these 1s and 0s culminate into, a complex analog wave that is derived from 44,100 points and some interpolation.
Dave