Joe Bloggs
Sponsor: HiByMember of the Trade: EFO Technologies Co, YanYin TechnologyHis Porta Corda walked the Green Mile
One effect that would be common to all headphones is the change in overall damping factor--the sound would supposedly be 'looser' than a 0 ohm impedance output, independent of changes in frequency response.
The other change, the change in frequency response, depends on the impedance response curves of the phones.
The power available to the phones at a particular frequency= V^2 / Z. The voltage V depends on the ratio of output impedance : headphone impedance at the frequency. Specifically,
V = Z(headphone) / Z(headphone) + Z(output).
The implication is that with 0 ohm output, the voltage across the headphones would be 100% of the output for all frequencies, while for higher ohm outputs, the higher the impedance of the headphones at a particular frequency, the higher the proportion of voltage available across the headphones. As output impedance tends to infinity, ratio of voltage available across the headphones for 2 frequencies = ratio of headphone impedance for those two frequencies.
I'll write more about this, but quick skinny is that headphones with an impedance hump in the low frequencies will end up with a low frequency response hump with high output impedance, while headphones with an impedance hump in the high frequencies will end up with a high frequency response hump. So the midbass hump of the HD580s will get worse with higher output impedance thanks to the midbass impedance hump, while the K501 may sound more shrill with higher impedance. Do the etymotics driver's impedance response look more like the K501 than the HD580?
The other change, the change in frequency response, depends on the impedance response curves of the phones.
The power available to the phones at a particular frequency= V^2 / Z. The voltage V depends on the ratio of output impedance : headphone impedance at the frequency. Specifically,
V = Z(headphone) / Z(headphone) + Z(output).
The implication is that with 0 ohm output, the voltage across the headphones would be 100% of the output for all frequencies, while for higher ohm outputs, the higher the impedance of the headphones at a particular frequency, the higher the proportion of voltage available across the headphones. As output impedance tends to infinity, ratio of voltage available across the headphones for 2 frequencies = ratio of headphone impedance for those two frequencies.
I'll write more about this, but quick skinny is that headphones with an impedance hump in the low frequencies will end up with a low frequency response hump with high output impedance, while headphones with an impedance hump in the high frequencies will end up with a high frequency response hump. So the midbass hump of the HD580s will get worse with higher output impedance thanks to the midbass impedance hump, while the K501 may sound more shrill with higher impedance. Do the etymotics driver's impedance response look more like the K501 than the HD580?
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