Mauricio
500+ Head-Fier
- Joined
- Feb 4, 2012
- Posts
- 634
- Likes
- 37
Quote:
Hear, measure? Relative to what? If I increase/decrease the volume is that the same?
Read this article.
Hear, measure? Relative to what? If I increase/decrease the volume is that the same?
I'm kind of struggling with interpreting this question. Is it about why electricity works the way it does, the general idea behind how to tell for a particular system, or specific tests to run to be able to tell for that particular system?
...Electrical filters are composed of capacitors (to block lows) and/or inductors (to block highs). As most components including phones and speakers contain elements having all of the above characteristics, non-uniform (non-linear) performance across a wide band of frequencies is difficult to avoid.
Originally Posted by Mauricio /img/forum/go_quote.gif
Conclusion 1: the amplifier drives its own output stage in parallel with the headphone
So the output impedance of an amplifier also varies with frequency?
Originally Posted by Isaansound /img/forum/go_quote.gif
Voltage accomplishes no work. Current is a better measure of work.
Originally Posted by Isaansound /img/forum/go_quote.gif
Low impedance phones are spoken of as being sensitive because a low impedance element will allow higher current, so it takes less "power" to drive them.
If you hope to get a good result with no amp, get low impedance phones, and choose a source (like a Fuze) that is good standing alone and likes low impedance loads. If you will be using an amp, then you can choose either type.
The output impedance and the headphone impedance are actually connected serially.
The output impedance and the headphone impedance are actually connected serially.
It can, for example if its output is capacitor coupled. This is common with low end sources that have a single power supply. For example, a 100 uF capacitor would have an impedance of 32 Ohm at 49.7 Hz, and with a 32 Ohm resistive load and insignificant output resistance, it would attenuate the signal by 3 dB. The same capacitor at 1 kHz has (in theory) only about 1.6 Ohm impedance, and the attenuation is insignificant at that frequency.
So if one shorts the output of an amplifier, the only load is the output impedance of the amplifier no matter how small it is, its not 0.
So what you are saying here is that if I sweep from 20Hz to 20kHz an amplifier using a 32 ohm purely resistive load, will I be able to see the dips from the amplifier's frequency response?