It gets on my nerves as well. This is just Shannon's sampling theorem - nothing mystical.
If you want to see something actually 'mystical' check this out (watch out like Shannon's Sampling Theorem math required).
There is this mathematical function, the so called zeta function which is ζ(s) = 1/1^s + 1/2^s + 1/3^s ......... Now put in k = 0, -1, - 2 etc and you get for k=0 1+1+1+1......, or k=-1 1 +2 + 3 etc. These look like infinity. But not so fast attendant reader - lets actually calculate it for all values -k.
∑(-1)^k*ζ(-k)*x^k/k! = ∑∑ n^k*(-x)^k/k! = ∑ ∑(-nx)^k/k! = ∑e^(-nx). Let S = ∑e^(-nx). e^xS = 1 + S so S = 1/e^x - 1 = 1/x*x/e^x - 1. But one of the definitions of the so called Bernoulli numbers Bk, is x/(e^x - 1) = ∑Bk*x^k/k! or taking the1/x into the sum S = ∑ B(k+1)*x^k/(k+1)! after changing the summation index so you still have powers of x^k. Thus you have ∑(-1)^k*ζ(-k)*x^k/k! = ∑ B(k+1)*x^k/(k+1)!. Equating the coefficients of the power of x^k you have ζ(-k) = (-1)^k*B(k+1)/k+1.
This result implies the bizarre identities ζ(0) = 1+1+1+1....... = -1/2 and ζ(1) = 1+2+3+4....... = -1/12.
Now that's magic - not like Shannon's sampling theorem that is simple basic engineering math. The why of the above is much more complicated - but unsuitable for here. You can do a bit of internet research on that one or go to a science forum and ask someone - I personally use Physics Forums. I will have to tell you though only some people actually understand it (technically it's got to do with complex analysis and avoiding the pole at s = 1 that causes the infinity - but that is likely meaningless unless you know complex analysis). You will hear all sorts of views like such sums are just definitions etc. In fact its used in calculations of real physical problems like the so called Casmir Force so is not just a definition - it has real physical consequences.
This is just to point out you cant really discuss this stuff, including what Rob does, without REALLY knowing the math behind it. English is a very poor medium for doing that. Rob has explained it many times - its simple math and the consequences irrefutable, but some just do not get it.
Thanks
Bill