Volume pot impedance question
Jan 22, 2007 at 2:36 AM Post #2 of 5
It's the amount by which the resistor/potentiometer is, well, resisting the flow of electric current.

http://en.wikipedia.org/wiki/Electrical_resistance can probably explain it better than I can.

EDIT: Rather, it's the maximum value of resistance for that given pot.
 
Jan 22, 2007 at 2:51 AM Post #3 of 5
Well as said it's the maximum value, so say a 100k pot would be 0-100k ohms theoritically, realistically they're not perfect.

Graphs are a good way to imagine the two most common types I know if there are others.

Linear is well a constant change in resistance accross the pots travel.

Audio however uses log pots, the resistance changes like a log graph, so you get a lot of fine control in the middle of travel and then at the start and end of travel the resistance increases/decrease in leaps and bounds.

I've got to ring up some wreckers at the moment, but if anyone hasn't already I'll get up a graph of each later.
 
Jan 22, 2007 at 3:07 AM Post #4 of 5
Yeah, probably should have mentioned that audio pots are logarithmic rather than linear (because the decibel scale is also logarithmic).
 
Jan 22, 2007 at 6:43 AM Post #5 of 5
How's this:
f_pottaperi_d772m_39b8ead.gif

Source: http://www.geofex.com/Article_Folder...s/potscret.htm
 

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