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So I was looking at the power supply crash course on TnT, and he calculates the required voltage this way:
Sq. Root of: (power * 2) * load impedance = peak voltage
Power being in Watts multiplied by two channels, and the impedance is 8 Ohms.
How did he get the following result?
Sq. Root of: (50 x 2)x8 = 28,284271V
Did he leave part of his math out? I cannot get this result!
Here is the link for reference:
http://www.tnt-audio.com/clinica/ssps2_e.html
Sq. Root of: (power * 2) * load impedance = peak voltage
Power being in Watts multiplied by two channels, and the impedance is 8 Ohms.
How did he get the following result?
Sq. Root of: (50 x 2)x8 = 28,284271V
Did he leave part of his math out? I cannot get this result!
Here is the link for reference:
http://www.tnt-audio.com/clinica/ssps2_e.html