[Shurephile]

I have these crazy division problems, and I need some assistance;
 
1. X^5 divided by X
 
2. A^2BC divided by ABC

 

[ProtegeManiac]

I'm a bit rusty so unless someone else confirms this, use this only as a last resort.
 
I.
X^5
  X
 
(X)(X)(X)(X)(X)
           X
 
X^4
 
 
II.
a^2bc
 abc
 
        a^2bc      
(a^1)(b^1)(c^1)
 
where:  division of like variables means subtracting the exponent of the divisor from the exponent of the dividend
 
a^2b-1
   bc 
 
(exponent of remaining a in dividend is 2b-1)

 

[superjawes]

ProtegeManiac, I think you dropped a "c" from the top of the fraction. I think the solution should be:

a^(2bc-1)
      bc


You solution to #1 is correct. Although, here are a couple more ways of thinking of it in hopes that it helps:

X^5 = X^5 = (X^5)*(X^-1) = X^4
  X      X^1

 

[ProtegeManiac]

ProtegeManiac, I think you dropped a "c" from the top of the fraction. I think the solution should be:

a^(2bc-1)
      bc


You solution to #1 is correct. Although, here are a couple more ways of thinking of it in hopes that it helps:

X^5 = X^5 = (X^5)*(X^-1) = X^4
  X      X^1

 
Whoops, typo 

 

[Folex]

The answer is always 42

 

[Solrighal]

The answer is always 42

Quoted for truth

 

[Kaeru92]

For 2) it all depends where you put the parenthesis.
Is it (a^2)*b*c or a^(2*b*c) ?

 

[Shurephile]

Here is another fun little problem. 
 
Belt and drive system: Large pulley (D) is 12.25", distance (C) to center of each pulley is 14.50", total linear length of belt (L) is 61.13". Calcuate the required diameter for the small pulley (d), formula is;
 
L=2C + 1.57(D+d) + 1/4 C(D-d)^2
 
 
So far I have this;
 
61.13"= 29+1.57 (12.25+d) +3.625 (12.25-d)^2

 

[fuego]

That friggin X is still missing? They've been looking for that X since I was 8.. lol