I need the help of an electronic engineer
Oct 27, 2007 at 12:51 PM Thread Starter Post #1 of 30

Firam

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It seems like there is a disproportionate number of electrical/electronic/computer engineers here. So I'll take a chance that someone knows. I'm stuck on a problem. How do I reduce this circuit? I want to use Wye to Delta but how does it work with capasitors?

circbb8.png


Thanks very much. So far my google searches have brought up nothing.
 
Oct 27, 2007 at 1:43 PM Post #2 of 30
eqiv C = 32/3F (I know this is wrong already..misread the schematic)

ok... I am 60% sure of my answer..someone check my answer!!!!

I should really be 100% sure of these 0 order circuits
frown.gif
 
Oct 27, 2007 at 2:58 PM Post #3 of 30
How did you get that answer?
 
Oct 27, 2007 at 3:03 PM Post #4 of 30
(1/(1/4+1/2))*2+8

can someone else verify this?
 
Oct 27, 2007 at 3:20 PM Post #5 of 30
Hmmm. You might be right but that looks strange. There are no caps in series or parallel, this is a three node circuit.

Looking at what you did, you add the 2F and 4F in series. Multiplied by two for both branches then added the 8F in parallel. So the equivalent circuit is:

circ2fo4.png


Which is exactly like the original one, except the 8F cap is moved. Can it go either place?
 
Oct 27, 2007 at 3:28 PM Post #6 of 30
look into the 8F and I see C4 and C1 in series, C5 and C2 in series.
 
Oct 27, 2007 at 3:38 PM Post #7 of 30
Quote:

Originally Posted by chesebert /img/forum/go_quote.gif
look into the 8F and I see C4 and C1 in series, C5 and C2 in series.


You look into the 8F. I don't understand. Maybe that is something we haven't covered.
 
Oct 27, 2007 at 3:46 PM Post #8 of 30
look into the nodes across 8F.

what's the right answer?
 
Oct 27, 2007 at 4:02 PM Post #9 of 30
I don't know the right answer. It is an extra credit problem for Physics, but since I know circuits I thought I could figure it out. I'll just ask my circuit teammates what they think. I wish I could just put it into Multisim/PSPICE but I can't figure out how I get them to measure capacitance.

I kinda see what you are talking about but don't quite understand it.
 
Oct 27, 2007 at 5:13 PM Post #10 of 30
Quote:

Originally Posted by Firam /img/forum/go_quote.gif
I don't know the right answer. It is an extra credit problem for Physics, but since I know circuits I thought I could figure it out. I'll just ask my circuit teammates what they think. I wish I could just put it into Multisim/PSPICE but I can't figure out how I get them to measure capacitance.

I kinda see what you are talking about but don't quite understand it.



life is easier when you use Cadence
wink.gif
 
Oct 27, 2007 at 6:37 PM Post #11 of 30
I just redrew the circuit..now I am serious questioning my answer. I was looking into the wrong end
wink.gif


I guess I wouldn't even reduce this circuit I just use nodal analysis..much easier IMO
wink.gif
damn the equiv circuit!
 
Oct 27, 2007 at 6:43 PM Post #12 of 30
Looks kinda like a wheatstone bridge circuit with caps in place of resistors.... interesting....
 
Oct 27, 2007 at 7:33 PM Post #13 of 30
ok..I used nodal analysis.

C3 is not even in the equation now! What

I just have C equiv = 1/(1/C1+1/C2) + 1/(1/C4+1/C5)
 
Oct 28, 2007 at 2:52 AM Post #14 of 30
bump..I need to know the answer. 165 views and no help...
 
Oct 28, 2007 at 3:01 AM Post #15 of 30
I'm wondering, if you assume steady state, wouldn't the voltage drop across the middle 8F cap be 0 and then we can disregard it? This then just becomes 2 sets of 2 caps in series in parallel.

I'm going to ask around to see if any of my friends can figure it out.
 

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