aCuria
Head-Fier
- Joined
- Apr 14, 2009
- Posts
- 70
- Likes
- 14
My current understanding of balanced connections:
In a regular balanced audio connection, we have the following:
R Channel: +R, -R, Rgnd
L Channel: +L, -L, Lgnd
The ground the ground wire surrounds the signal wires and is used as a shield against some interference. Unlike an unbalanced setup, the ground wire does not carry a signal.
Lets consider the right channel, 2 signals are sent out of phase from each other, say from the preamp to the power amp, we call this a differential signal:
+R and -R
Along the way from the preamp to the power amp, both signals pick up some form of noise because of electromagnetic induction. The noise is in phase (identical in both signals), so we have
(+R + N) and (-R + N)
In the power amp, the signals are passed into a differential amplifier, which is a type of electronic amplifier that amplifies the difference between two input voltages but suppresses any voltage common to the two inputs.
(+R + N) - (-R + N)
= +R + N +R - N
= 2R
In this way, the differential amplifier is able to remove the noise from a signal.
What I don't understand
1) For balanced headphones, how does the balanced connection reject noise without a differential amplifier?
2) Why is there no ground built into balanced headphone cables?
In a regular balanced audio connection, we have the following:
R Channel: +R, -R, Rgnd
L Channel: +L, -L, Lgnd
The ground the ground wire surrounds the signal wires and is used as a shield against some interference. Unlike an unbalanced setup, the ground wire does not carry a signal.
Lets consider the right channel, 2 signals are sent out of phase from each other, say from the preamp to the power amp, we call this a differential signal:
+R and -R
Along the way from the preamp to the power amp, both signals pick up some form of noise because of electromagnetic induction. The noise is in phase (identical in both signals), so we have
(+R + N) and (-R + N)
In the power amp, the signals are passed into a differential amplifier, which is a type of electronic amplifier that amplifies the difference between two input voltages but suppresses any voltage common to the two inputs.
(+R + N) - (-R + N)
= +R + N +R - N
= 2R
In this way, the differential amplifier is able to remove the noise from a signal.
What I don't understand
1) For balanced headphones, how does the balanced connection reject noise without a differential amplifier?
2) Why is there no ground built into balanced headphone cables?