BavariaBarbarian
100+ Head-Fier
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- Nov 26, 2004
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Well, this may be a stupid question, but well: Anybody tries to embarass himself as best he may...
I'd like to plop two Nimh rechargeables into my Cmoy instead of using Alkalines.
The thing is: I read once that one should never, ever deep-discharge a nimh battery below 0.6 or so Volts per cell or it may get damaged.
So now i figure: One battery has 8.4 V so there's gotta be 7 1.2 V cells in a row in there - correct?
If so, and i deplete them to 0,6 V each in both batteries I'll get 7*2* 0.6V = 8.4V.
So methinks i won't hear any clipping due to low supply voltage and go on listening until i've squeezed the last electron out of those batteries.
(Which can't be long from that point on... but anyway.)
Am i making any sense? At all?
Because, you see, it wouldn't save me much money if i killed my rechargeables by deep-discharge after a few cycles.
I'd like to plop two Nimh rechargeables into my Cmoy instead of using Alkalines.
The thing is: I read once that one should never, ever deep-discharge a nimh battery below 0.6 or so Volts per cell or it may get damaged.
So now i figure: One battery has 8.4 V so there's gotta be 7 1.2 V cells in a row in there - correct?
If so, and i deplete them to 0,6 V each in both batteries I'll get 7*2* 0.6V = 8.4V.
So methinks i won't hear any clipping due to low supply voltage and go on listening until i've squeezed the last electron out of those batteries.
(Which can't be long from that point on... but anyway.)
Am i making any sense? At all?
Because, you see, it wouldn't save me much money if i killed my rechargeables by deep-discharge after a few cycles.