dhp
(formerly known as DieInAFire)
- Joined
- Sep 14, 2005
- Posts
- 1,881
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- 11
I'm posting on behalf of a friend (I'm helping him build his amp..) I have his PPA board so I can troubleshoot it here.. the problem is this.
Yesterday his PPA powered up fine, no problems at all and he wired up panel components.. Took the PPA home, today worked on it again... realized he forgot to adjust the buffer bias.
While adjusting buffer bias he shorts output resistor to one of the legs on Q33 (output transistor).. We dont notice and scratch our heads wondering why meter reads OL. I touch the top of the TO-92 and it's HOT.. burn-like warmth and I start to smell solder so we turn it off and desolder the TO-92s from the left channel..
Thinking that we could adjust the bias on the other two, we power up the amp again, this time TO-92s arnt hot, but the R-23 burns a hole through itself and we quickly shut off the PPA and call it a day.. my question is this
Why would the R-23 burn? It's rated for 1/4 watt at 2.2 ohms so that's 1/4=I^2*R. so I^2 = 1/8 amp. so that resistor would have to pass about .35 amps through when the Q-23 can only output 50 mA... whats going on here?
Oh and we get to replace the entirety of ground/left/right buffers.. just to be safe =p
Yesterday his PPA powered up fine, no problems at all and he wired up panel components.. Took the PPA home, today worked on it again... realized he forgot to adjust the buffer bias.
While adjusting buffer bias he shorts output resistor to one of the legs on Q33 (output transistor).. We dont notice and scratch our heads wondering why meter reads OL. I touch the top of the TO-92 and it's HOT.. burn-like warmth and I start to smell solder so we turn it off and desolder the TO-92s from the left channel..
Thinking that we could adjust the bias on the other two, we power up the amp again, this time TO-92s arnt hot, but the R-23 burns a hole through itself and we quickly shut off the PPA and call it a day.. my question is this
Why would the R-23 burn? It's rated for 1/4 watt at 2.2 ohms so that's 1/4=I^2*R. so I^2 = 1/8 amp. so that resistor would have to pass about .35 amps through when the Q-23 can only output 50 mA... whats going on here?
Oh and we get to replace the entirety of ground/left/right buffers.. just to be safe =p