Do I have an ER-4P or ER-4S?
Dec 18, 2008 at 3:03 AM Thread Starter Post #1 of 12

busyx2

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Hi,
I don't know what I've got now...
confused_face_2.gif


When I measure with a DMM, I found 100-ohm impedance on the earphones, is this a P or S?
 
Dec 18, 2008 at 4:14 AM Post #6 of 12
Quote:

Originally Posted by TacticalPenguin /img/forum/go_quote.gif
you cant go S->P but you can go P (26ish) -(+75)> S (100ish)

you have S and cant go to P without a new cable



That´s what I thought as well
 
Dec 18, 2008 at 4:33 AM Post #7 of 12
Quote:

Originally Posted by busyx2 /img/forum/go_quote.gif
Hmmm, can I parallel a 36 Ohm resistor to turn the 'S' into a 'P'?

1/100 + 1/36 = 1/27



Technically you "could" do that, but you'd have to take apart the headphones and splice out the existing resister and add one in parallel with it there. Might as well replace it if you're doing that kind of surgery.

I wouldn't recommend it for obvious reasons
smily_headphones1.gif
 
Dec 18, 2008 at 6:40 AM Post #8 of 12
No, what I meant was to parallel a 36 Ohm resistor at the input plug.

Since the driver is in series with a 100-Ohm resistor, then in parallel with a 36 ohm resistor:

(100 Ohm + Driver)//36 Ohm = 27 Ohm

No need to take apart any cable, just solder to the plug, or an adapter.
 
Dec 18, 2008 at 6:43 AM Post #9 of 12
Quote:

Originally Posted by dan1son /img/forum/go_quote.gif
, but you'd have to take apart the headphones and splice out the existing resister and add one in parallel with it there.


Since the Knowles driver is practically 0-ohm, I can parallel the resistor at the input plug, instead of // on the 100-ohm resistor. Hope this make things clear. In fact, I've already tried, and it seems to sound more transparent.
 
Dec 18, 2008 at 7:44 AM Post #12 of 12
Still sounds like you have have added additional resistance to it, adding the impedance cable to the P-version gives
it a more clearer or transparant sound, but also means you have the increase the volume to receive or hear the same output
 

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