Mullet
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I'm a bit confused in terms of your math and reading about the circuit on this thread. Based on the given formula, I was under the impression that 75 ohm resistor would be fine because 1.25/75 would come out to 16mA, which would come out to around 16 hours to charge the batteries. I haven't read anywhere about being aware of a voltage drop. Just that you want to have a supply that has more voltage than the batteries in series. Maybe I'm missing something.
With regard to measuring the current, my MM doesn't read Amperage. Instead, could I use any value resistor and measure the voltage across that? I have nothing that is super low other than a 1 ohm resistor that measures 1.2 ohms. I do have a few 1k ohm resistors. Would those work better?
With regard to measuring the current, my MM doesn't read Amperage. Instead, could I use any value resistor and measure the voltage across that? I have nothing that is super low other than a 1 ohm resistor that measures 1.2 ohms. I do have a few 1k ohm resistors. Would those work better?