chillysalsa
Headphoneus Supremus
- Joined
- Sep 26, 2002
- Posts
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Just trying to make some interconnects that will drop my CD player output by 6 or 10 dB, since the amp gain (on the integrated amp for speakers) is pretty high and my speakers are sensitive.
So I figure I will just use a simple voltage divider:
in which the interconnect will have a resistor R(in) in series with the hot/signal connection, and R(g) from the signal wire to the ground/shield.
So, R(in) + R(g) is the resistance of the interconnect (without knowing the capacitance we can't calculate the true impedance of it, right?). But still, what is this value ideally supposed to be???
My source is 2V output, and amp had input impedance of 100K.
So I figure I will just use a simple voltage divider:
in which the interconnect will have a resistor R(in) in series with the hot/signal connection, and R(g) from the signal wire to the ground/shield.
So, R(in) + R(g) is the resistance of the interconnect (without knowing the capacitance we can't calculate the true impedance of it, right?). But still, what is this value ideally supposed to be???
My source is 2V output, and amp had input impedance of 100K.