Ok, finally have more than a few minutes to bang out a reply.
When using speaker amps to drive headphones, unless the amp has rather low rated power into loudspeaker loads, you often have to deal with excess gain, i.e. a speaker amp will typically have a lot more gain than is required to drive a typical headphone to sufficient levels. This means you'll have a lot less useable range on the volume control.
So basically, short of reducing the gain of the amplifier, you need to attenuate the amp's output. The simplest way is with a single resistor in series with the amp's output. This forms a voltage divider consisting of the series resistor and the headphone's impedance. A secondary effect of this is to increase the output impedance of the amp by the amount of resistance of the resistor. This doesn't present a problem for orthos which have a flat, virtually purely resistive impedance, but can be problematic with dynamic headphones which don't.
This can be addressed by adding a second resistor that's in parallel with the headphones. And in that case, the source impedance seen by the headphones is the parallel combination of the series resistor and the resistor across the headphone (technically the amp's inherent output impedance of the amp is added to the series resistor, but the series resistor will typically be much higher than that so it can often be ignored).
As for noise, the voltage divider will attenuate everything, noise and music, because of course a resistor can't tell the difference between the two. So any quiescent noise produced by the amplifier won't be quite so loud which is of benefit for headphones with high sensitivity.
This help?
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