Coin, this is how I see this thing working.
Our WCF uses a DC servo to null the DC at the output.
A "DC servo" does not "
nullify the DC at the output", only output transformers or ouput capacitors can do that, in my book. And we don't have any of those in either the MK6 or MK8. More of that below.
My understanding is that this "DC servo" is only
monitoring the output. I confess I didn't pay much attention to it as it is not supposed to be in the signal path.
Whatever, when the "what it is monitoting" (voltage or current) exceeds the programmed value, it triggers the relay and cut the output.
Plain and simple.
The only time the DC is zero at the output is when both tubes have a matching impedance, therefore the servo maintains an equal impedance between them.
You should be more precise about what is your reference voltage. Here it really matters as it differs between "SE operation" and "symetrical".
The output voltage of an OCL WCF is roughly half the rail voltage, minus the voltage drops due to the Ra and Rk. Basically,
100V for a 200V power rail. The voltage reference is taken at the bottom rail, below the cathode.
And basically the only thing that can change this 100V voltage would be to have a significant unbalance between the internal resistance of the two triode of the tube.
Whatever tube you put, intil they have the same internal resistance, they will output the same 100V.
So what ?
When running symetrical, both tubes of a channel are running at 100V. The "difference in potential" (
not sure of the trad. here) which is the true definition of a voltage by the way is 100V - 100V => 0V.
So, we don't get electrocuted ! Nice !
When running SE, it's a bit more tricky ! Only one tube is being used and its WCF is still outputing 100V. But we need to have a "difference in potential" of 0V at the headphone if we want to not fry everything ...
That's why the "ground" of the SE plug is not linked to the rail ground but to the "mid-point" of the power PSU where the potential is also at 100V above the one of the "rail ground".
And then TA DA !!! we have our equilibrium/balance between potential as they are seen by the headphone : 100V - 100V = 0V.
Changing the plate resistor value [...] will probably cause a required uneven impedance between the tubes to maintain a 0v output
I don't see why we would end up with an "uneven impedance between the tubes" when we have applied the same Ra for both tubes of a channel.
... and it will alter the intended load line operating point of 75ma/75v on the MK6 which is what the amp was designed for given its voltage swing (which is close to cutoff to begin with which is why the NFB is needed).
You're right in saying that it will change the "operating point". That's a good point.
And it would be bothering that by lowering the Rplate we increase the plate current above the "max Ia specs". We'll have a look into that.