jodgey4
Headphoneus Supremus
- Joined
- May 2, 2013
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An amp transfers max power to a load equal to it's output resistance. To calculate the volume of a headphone, you need to know impedance and sensitivity. Sensitivity is given best in some db / 1mW. For each 3 dB increase in volume, you double the power needed. So if sensitivity is 106 db / 1 mW, then to get 109 dB, you need 2 mW. To get 121 dB, you need 32 mW. To calculate how much power an amp can deliver to your headphones, use the power relationship Power = V^2 / R. If an amp can do 1 W into 32 ohms, then it can do 27 mW into 1200 ohms, which would be about 120 dB. (The voltage is the same for both cases, so solve for V and divide by whatever your impedance is. So at 106 dB / 1 mW, the LCD-Z's are actually quite easy to drive!
The impedance is indeed very high because of the high number/density of traces, and the sensitivity comes from the fact that there is so much more surface area for the magnets to affect, that you get a much more efficient transfer of energy.
The impedance is indeed very high because of the high number/density of traces, and the sensitivity comes from the fact that there is so much more surface area for the magnets to affect, that you get a much more efficient transfer of energy.