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Cut Off Frequency with Pot on Cmoy

post #1 of 2
Thread Starter 

Could you help me to calculate the cut off frequency with the following schematic:

 

C2= 0.0000001 F (0.1uF)
R2= 22000 (22K)
fc= 72.34 Hz at -3dB

 

If I add a 10 K pot at middle position Do I have to make parallel 5K||5k = 2.5K and add it to 22K to get 24.5K ?

C2= 0.0000001 F (0.1uF)
R= 24500 (22k + 2.5k = 24.5K)
fc= 64.96 Hz at -3dB


Is correct the cutoff frequency including the pot?

 

Alfredo Mendiola Loyola

Lima, Peru


Edited by mendiola - 6/16/14 at 11:20am
post #2 of 2
Thread Starter 
Quote:
Originally Posted by mendiola View Post

Could you help me to calculate the cut off frequency with the following schematic:



 



C2= 0.0000001 F (0.1uF)

R2= 22000 (22K)

fc= 72.34 Hz at -3dB



 



If I add a 10 K pot at middle position Do I have to make parallel 5K||5k = 2.5K and add it to 22K to get 24.5K ?



C2= 0.0000001 F (0.1uF)

R= 24500 (22k + 2.5k = 24.5K)

fc= 64.96 Hz at -3dB





Is correct the cutoff frequency including the pot?





 



Alfredo Mendiola Loyola



Lima, Peru


 



It also applies to inverting input
Moving the wiper to the mid position and high pass filter??

Full-up, assuming low source impedance: bass cutoff is 0.1uFd against 100K or 15.92Hz.
way-down: bass cutoff is again 0.1uFd against 100K or 15.92Hz.
At "half loudness": bass cutoff is 0.1uFd against 100K+2K5 or 15.54Hz.
No difference except with careful measurement.
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