What does this mean?
Jul 20, 2003 at 3:09 PM Thread Starter Post #1 of 6

NEPS

New Head-Fier
Joined
Jul 20, 2003
Posts
8
Likes
0
I just want to know what is this mean.

quote:
--------------------------------------------------------------------------------
Originally posted by d_wilson
The iPod has good sound, but the caps are too small to drive lower impedances. That said more people like the lower impedance ER-4P with it than the higher impedance ER-4S or ER-6.
--------------------------------------------------------------------------------


D_wilson said Ipod's caps are too small to drive lower impedances.
And use lower impedances er4p with Ipod.
What is this mean? What's wrong?
 
Jul 20, 2003 at 4:02 PM Post #2 of 6
Not sure about the context that quote came from. I'd guess he's talking about coupling capacitors on the iPods output , which would be there to eliminate any DC from the output. In combination with the impedance of the headphones, they form a highpass filter. The corner frequency is determined by the size of the caps (more capacity -> lower cutoff) and the headphone impedance (less impedance -> higher cutoff). I don't know any specifics about the iPod, but what Don seems to say is that with the combination ER-4P/iPod the attenuation starts high enough to be noticeable.
 
Jul 20, 2003 at 5:33 PM Post #3 of 6
Peter, your definition is dead-on.

peacesign.gif
 
Jul 20, 2003 at 5:55 PM Post #4 of 6
That's an interesting point which I never really gave any serious thought to before. I suppose it's true with practically any portable player these days. On the iPod it may make additional sense as the EQ sucks a bit.
 
Jul 20, 2003 at 6:16 PM Post #5 of 6
attachment.php


Measured by «stereoplay», April 2002
.
 

Users who are viewing this thread

Back
Top