# Line slope calculator x-3y=2

**Straight line given by points A[2; 0] and B[5; 1]**

## Calculation:

**Slope-intercept form of line:**y = 0.3333x-0.6667

**Canonical form of the line equation:**x-3y-2 = 0

**Parametric form of the line equation:**

x = 3t+2

y = t ; t ∈ R

**Slope:**m = 0.3333

**Slope angle of line: φ =**18°26'6″ = 0.3218 rad

**X intercept:**x

_{0}= 2

**Y intercept:**y

_{0}= q = -0.6667

**Distance line from the origin:**d

_{0}= 0.6325

**The length of the segment AB: |AB| =**3.1623

**Vector: AB =**(3; 1)

**Normal vector: n =**(1; -3)

**Midpoint of the segment AB: M =**[3.5; 0.5]

**Perpendicular Bisector equation:**3x+y-11 = 0

**Vector OA = (2; 0) ; |OA| = 2**

**Vector OB = (5; 1) ; |OB| = 5.099**

**Scalar product OA .OB = 10**

**Angle ∠ AOB = 11°18'36″ = 0.1974 rad**