Post your question in the Comment section below, and a GRE expert will answer it as fast as humanly possible.

- Video Course
- Video Course Overview
- General GRE Info and Strategies - 7 videos (free)
- Quantitative Comparison - 7 videos (free)
- Arithmetic - 42 videos
- Powers and Roots - 43 videos
- Algebra and Equation Solving - 78 videos
- Word Problems - 54 videos
- Geometry - 48 videos
- Integer Properties - 34 videos
- Statistics - 28 videos
- Counting - 27 videos
- Probability - 25 videos
- Data Interpretation - 24 videos
- Analytical Writing - 9 videos (free)
- Sentence Equivalence - 39 videos (free)
- Text Completion - 51 videos
- Reading Comprehension - 16 videos

- Study Guide
- About
- Office Hours
- Extras
- Prices

## Comment on

Writing Equations## How did you get the 4m+15 for

## I didn't get 4M+15 for Curly

I didn't get 4M+15 for Curly's age.

I got 2(M+5) for Curly's age.

I also got M+5 for Larry's age

And I got M for Moe's age

We are told that the sum of all 3 ages is 95

So, we get: M + M+5 + 2(M+5) = 95

When we simplify the left side of the equation, we get 4M+15 = 95

So, 4M+15 is a simplification of the left side of the equation (which represents the sum of all 3 men)

## Hello, I have a question

For both a and b , I had a problem with solving the question.

Need your kind explanation on both question. Thank you

## You bet.

You bet.

THE QUESTIONS:

A group can charter a particular aircraft at a fixed total cost. If 36 people charter the aircraft rather than 40 people, then the cost per person is greater by $12.

(A) What is the fixed total cost to charter the aircraft?

(B) What is the cost per person if 40 people charter the aircraft?

-----QUESTION A--------------

Let T = TOTAL price of charter

With 36 people, the price PER PERSON = T/36

With 40 people, the price PER PERSON = T/40

We're told that the price PER PERSON with 36 people is $12 greater than the price PER PERSON with 40 people.

In other words: price PER PERSON with 36 people is $12 MORE than the price PER PERSON with 40 people

Or: (price PER PERSON with 36 people) = (price PER PERSON with 40 people) + $12

Now we can write: T/36 = T/40 + 12 (solve for T)

To eliminate the fractions, multiply both sides by 360 to get: 10T = 9T + 4320

Solve: T = 4320

So, the TOTAL price of the charter = $4320

-----QUESTION B--------------

From above, we know that the TOTAL price of the charter = $4320

With 40 people, the price PER PERSON = T/40

So, the price PER PERSON = 4320/40 = $108

So, each person pays $108

Does that help?

Cheers,

Brent

## Understood. Thank you

## Thanks for the solution guys

## wow.. I am able to track the

## Hi Reetika,

Hi Reetika,

Glad you like the change!!

Cheers,

Brent

## Official Guide to the GRE

x + y = 3000

0.08x + 0.1y = 256

This gave me an incorrect answer.

I subsequently switched the variables to get: 0.1x + 0.08y = 256

This gave me the correct answer.

I'm confused as to why would not the earlier equation work?

## The two systems you created

The two systems you created should both give you the correct answer.

Think of it this way:

If we let x = amount of money that earned 8% interest,

...and we let y = amount of money that earned 10% interest

Then the first system is perfect

If we let y = amount of money that earned 8% interest,

...and we let x = amount of money that earned 10% interest

Then the second system is perfect

So, either system should have worked.

Given this, I have a feeling you made a small error while solving the first system.

If you want to post your solution for the first system, I can probably find the point where the solution went "off the rails"

Cheers,

Brent

## https://greprepclub.com/forum

Hello Brent i was on the right track in assigning variables on this questions till i saw this last part "matt owns 100 houses more than Angela". I tried to assign a variable and i couldn't. I checked the solution and found out they didn't even use the variable i found hard to decipher. How do i know what's necessary in a word problem question

## Question link: https:/

Question link: https://greprepclub.com/forum/each-of-the-576-houses-in-tenantville-is-o...

Interesting! I never realized that I never used the fact that Matt owns 100 houses more than Angela.

That said, it looks like that information was unnecessary.

It's VERY rare that a GRE question will contain superfluous information, so I wouldn't worry about it.

Cheers,

Brent

## Jennifer has 60 dollars more

Please solve i started off with B=Brian

B+60= Jennifer

## Here's my full solution: http

Here's my full solution: http://www.urch.com/forums/gre-math/155943-help-me-question-please-prope...

Cheers,

Brent

## http://www.urch.com/forums

I face just one problem in this question, Why are we not subtracting 25% or 0.4% from this equation, i.e, 0.8(60+X) when Jennifer was to give Brian 1/5 of her money and Brian would have 25% less than the amount that Jennifer would then have?

Thanks for your help Brent!

## Question link: http://www

Question link: http://www.urch.com/forums/gre-math/155943-help-me-question-please-prope...

Subtracting 25% is the same as keeping 75%.

For example, if a toy costs $100, then a 25% off sale, means a buyer must PAY 75% of the original price.

Or we can say that a buyer must PAY 3/4 of the original price.

That's the rationale I used in my solution.

Does that help?

Cheers,

Brent

## Thanks, it does help a lot.

2x=0.4-60.

Where did I go wrong? I am not sure.

Thanks again for all the help!

## Hi Ketan,

Hi Ketan,

Can you provide a more detailed, step-by-step solution?

At the moment, it's unclear to me what the 0.4 stands for.

Cheers,

Brent

## Here's what I did: x+0.2(60+x

x+12+0.2x=0.4-48-0.8x

1.2x+12=0.4-48-0.8x

2x=0.4-48-12

2x=0.4-60

This is where I am stuck. Thanks for the assistance.

## What does 25/100 represent?

What does 25/100 represent?

Also, 25/100 = 0.25 (not 0.4)

## Thanks for highlighting the

## You can't just subtract 25%.

You can't just subtract 25%.

You must subtract 25% OF SOMETHING.

If Joe has J dollars, and I have 25% less than Joe, then...

The amount of money I have = (Joe's money) - (25% of Joe's money)

= J - (25% of J)

= J - 0.25J

= 0.75J

-------------------------

Here's my full solution (starting with your approach)

Let x = Brian's money NOW

So, x + 60 = Jennifer's money NOW

GIVEN: Jennifer gives Brian 1/5 (20%) of her money

20% of Jennifer's money = 0.2(x + 60) = 0.2x + 12

So, at this point....

x + (0.2x + 12) = Brian's money

x + 60 - (0.2x + 12) = Jennifer's money

Simplify to get:

1.2x + 12 = Brian's money

0.8x + 48 = Jennifer's money

GIVEN: At this point, Brian has 25% less than the amount that Jennifer has.

25% of Jennifer's money = 0.25(0.8x + 48)

= 0.2x + 12

So, 25% LESS THAN Jennifer's money = 0.8x + 48 - (0.2x + 12)

= 0.6x + 36

We can write: 1.2x + 12 = 0.6x + 36

Solve: x = 40

So, Brian has $40 NOW, which means Jennifer has $100 NOW.

Does that help?

Cheers,

Brent

## It is clear to me now. Thanks

## Regarding the 2nd from last

## You made a very small mistake

You made a very small mistake. My response here: https://greprepclub.com/forum/a-sum-of-money-was-distributed-among-lyle-...

Cheers,

Brent

## Hello Brent!

https://m.youtube.com/watch?v=glnQsBkkEhM

Can you explain please how does he gets 28?

I find the value of M =4

Then if now he is 4 years in 12 years he will be 16

4*M=16

So

16x=32*12

x=24

## Question link: https://m

Question link: https://m.youtube.com/watch?v=glnQsBkkEhM

We must find the "number of years until Murray is 8 times as old as he is now"

M = 4. so Murray is NOW 4 years old.

8 x 4 = 32

So, 8 times Murray's PRESENT age equals 32.

So, we must determine the number of years until Murray is 32

Murray is NOW 4 years old.

So, he will be 32 years old in 28 years.

## I a little confused about as

1- The three consecutive integers :

F= first no.

F+1 = second no

F+2 = third no.

2- The 4 consecutive odd number )

A). (.....,1, 3, 5, 7, 9, 11, 13,.......)

F = first no

F+2 =second no

F+4 = third no

F+6 = forth no

B).

F+1 = first integers

F+2 = second

F+ 3 = third

F+5 = forth

F+7 = Fifth

Thanks

## 1) With consecutive integers

1) With consecutive integers (e.g., 4,5,6,7,8...), each integer is ONE GREATER than the previous integer.

So, as you suggest, we get:

F = first #

F + 1 = second #

F + 2 = third #

etc.

2) With consecutive ODD integers (e.g., 5,7,9,11,13,15...), each integer is TWO GREATER than the previous integer.

So, we get:

F = first #

F + 2 = second #

F + 4 = third #

F + 6 = fourth #

etc.

We can verify this assignment by seeing what happens if we let F = some odd number.

For example, if F = 11, then we get:

F = 11 = first #

F + 2 = 11 + 2 = 13 = second #

F + 4 = 11 + 4 = 15 = third #

F + 6 = 11 + 6 = 17 = fourth #

etc.

Let's keep going.....

3) With consecutive EVEN integers (e.g., 4,6,8,10,12...), each integer is TWO GREATER than the previous integer.

So, we get:

F = first #

F + 2 = second #

F + 4 = third #

F + 6 = fourth #

etc.

Does that help?

## Hi Brent,

regarding this https://greprepclub.com/forum/qotd-13-at-a-club-meeting-there-are-10-more-club-members-2494.html

non-club members =n

club members =n+10

GIVEN: There are 10 more club members than non-members.

so n+n+10=c

2n+10=c

2n=c-10

n=(c-10)/2

Could you please help me with this.

Thanks

suppose total club umbers=c

## Question link: https:/

Question link: https://greprepclub.com/forum/qotd-13-at-a-club-meeting-there-are-10-mor...

We're told that c = number of CLUB MEMBERS at the meeting

In your solution, you have n + n + 10 = c, which means c = total number of people (MEMBERS and NON-MEMBERS) at the meeting.

I hope that helps.

Cheers,

Brent

## Hi Brent,

Sorry I Didnt get you

Thanks

## You let n = non-club members

You let n = non-club members

So, club members =n+10

GIVEN: There are 10 more club members than non-members.

So n + n + 10 = c

So, you are saying that (non-club members) + (club members) = c

However, this not what the question is telling us.

The question tells us that c = number of CLUB MEMBERS at the meeting.

You are saying that n + 10 = number of CLUB MEMBERS at the meeting.

So, you don't need to create a new variable (n) to describe anything.

You need only use the variable c.

Does that help?

## https://gmatclub.com/forum

For this problem I was able to break it down and understand what they wanted me to find. However I started at yr 1, instead of beginning at yr 0, is it usually the case that we would begin at yr 0.

What I did yr1: x, yr2: 5x/4: yr3:25x/16, yr4: 125x/64 and set the value in yr 4 to6250, but that was incorrect. When I looked at the solution I was off by 1 yr hence starting from yr 0. Hope this all makes sense. Please let me know if you need any clarification. Thanks and happy holidays!

## Labelling the years "year1",

Labelling the years "year1", "year2", "year3" is ambiguous.

For example, what does it mean to say that year1 = x?

Does it mean the population was x at the BEGINNING of the first year or at the END of the first year?

The question tells us, "....there were 6250 trees in the orchard AT THE END OF a 4-year period"

In other words, after 4 years have ELAPSED, there were 6250 trees.

So, we should start at the beginning, before any years have elapsed (i.e., 0 years have elapsed), and go from there.

BTW, here's my solution: https://gmatclub.com/forum/each-year-for-4-years-a-farmer-increased-the-...

## https://gmatclub.com/forum/a

Hey Brent I came across this question and for some reason I am having difficulty with it. I went ahead and decided to set up equations for it: Beginning 93': SC+FB = 100

(During 93'): 1.033SC +1.033FB = 103.5

## Question link: https:/

Question link: https://gmatclub.com/forum/a-survey-of-employers-found-that-during-1993-...

Your equation SC + FB = 100 tells us that, at the beginning of 1993, the total EMPLOYMENT COSTS were $100

If SC increased 3% and FP increased 5.5%, then NEW SC = 1.03SC and NEW FB = 1.055FB

Likewise, since EMPLOYMENT COSTS increased 3.5%, then the NEW EMPLOYMENT COSTS = (1.035)($100)

So, our equation becomes: 1.03SC + 1.055FB = (1.035)($100)

In other words, 1.03SC + 1.055FB = 103.5

We now have the following system of equations:

1.03SC + 1.055FB = 103.5

SC + FB = 100

When we solve this, we get SC = 80 and FB = 20

20/100 = 20%

So, fringe-benefit costs represented 20% of employment costs at the beginning of 1993