a question for the tech-heads
Nov 8, 2001 at 5:51 AM Post #16 of 16
Quote:

Originally posted by Xevion
coolvij - Thats the thing, it dosen't make it "harder" for the power to move. In fact in a parallel circut with a high resistance resistor and a low resistance resistor, the high resistance resistor will be the one dissapating more heat (wattage) which is kind of the inverse of what you are thinking but isn't really. It is rather hard to explain adequately. Ah, well, later tonight I will post the equations and the numbers and you can draw your own conclusions on what to call it.
smily_headphones1.gif


Sorry, but this is backwards. I was gonna keep my mouth shut, but I couldn't help it. Sorry...

Power in watts (disapated) = Volts^2 / Resistance

So

10 volts across 16 ohms will dissapate 6.25 watts

and

10 volts across 8 ohms will dissapate 12.5 watts

Parallel resistance is calculated by the reciprocal of the sum of the reciprocals. So...

8 and 16 ohms in parallel with one another is 5.3 ohms

and

10 volts across 5.3 ohms will dissapate 18.75 watts

It all adds up.
smily_headphones1.gif
 

Users who are viewing this thread

Back
Top