kwkarth
Electronics guys... we have our plusses and minuses. With advent of digital everything, we're being phased out
- Joined
- Sep 30, 2001
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Quote:
Sorry, but this is backwards. I was gonna keep my mouth shut, but I couldn't help it. Sorry...
Power in watts (disapated) = Volts^2 / Resistance
So
10 volts across 16 ohms will dissapate 6.25 watts
and
10 volts across 8 ohms will dissapate 12.5 watts
Parallel resistance is calculated by the reciprocal of the sum of the reciprocals. So...
8 and 16 ohms in parallel with one another is 5.3 ohms
and
10 volts across 5.3 ohms will dissapate 18.75 watts
It all adds up.
Originally posted by Xevion coolvij - Thats the thing, it dosen't make it "harder" for the power to move. In fact in a parallel circut with a high resistance resistor and a low resistance resistor, the high resistance resistor will be the one dissapating more heat (wattage) which is kind of the inverse of what you are thinking but isn't really. It is rather hard to explain adequately. Ah, well, later tonight I will post the equations and the numbers and you can draw your own conclusions on what to call it. |
Sorry, but this is backwards. I was gonna keep my mouth shut, but I couldn't help it. Sorry...
Power in watts (disapated) = Volts^2 / Resistance
So
10 volts across 16 ohms will dissapate 6.25 watts
and
10 volts across 8 ohms will dissapate 12.5 watts
Parallel resistance is calculated by the reciprocal of the sum of the reciprocals. So...
8 and 16 ohms in parallel with one another is 5.3 ohms
and
10 volts across 5.3 ohms will dissapate 18.75 watts
It all adds up.