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# Technical question about output power of an amp

If an amp's spec says it has a maximum of 5W power at 32 Ohms , how can we figure out the maximum output power at a different impedance  say, at 600 ohm ?

I am guessing it cannot be determined ?

do I have to look at the amp's maximum voltage output ?

Guess I figured it out.... I use the max output voltage then choose my impedance find I using the Ohm's law then P=I*V

Am I correct ?

Edited by Sam21 - 6/23/14 at 5:42pm

A very rough approximation would be:

P2 = P1 * R1 / R2

In your example that gives 0.27W @ 600 Ohm.

Quote:
Originally Posted by Sam21

If an amp's spec says it has a maximum of 5W power at 32 Ohms , how can we figure out the maximum output power at a different impedance  say, at 600 ohm ?

I am guessing it cannot be determined ?

You can't do that reliably. Some amps are better at low impedance output. Some at higher impedance.
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