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post #16 of 22
9/28/12 at 6:51am
Thread Starter 

Is the Fiio E17 better then the Fiio E10 ?.

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post #17 of 22
9/28/12 at 8:02am
Quote:
Originally Posted by rei075 View Post

Is the Fiio E17 better then the Fiio E10 ?.
Yes.
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post #18 of 22
3/20/13 at 7:51pm
Quote:
Originally Posted by rei075 View Post

Is the Fiio E17 better then the Fiio E10 ?.

 

17 - 10 = 7

 

The E17 is 7 times better than the E10.

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post #19 of 22
3/20/13 at 7:55pm

Brilliant!

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post #20 of 22
3/20/13 at 8:04pm
Quote:
Originally Posted by OperatorPerry View Post

 

17 - 10 = 7

 

The E17 is 7 times better than the E10.

 

Not quite:

 

17/10 = 1.7

 

So the E17 is only 1.7 times better.

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post #21 of 22
3/21/13 at 6:39pm
Quote:
Originally Posted by KimLaroux View Post

 

Not quite:

 

17/10 = 1.7

 

So the E17 is only 1.7 times better.

 

No, that's not how Fiio product numbering works.  Fiio uses the Riemann zeta function to relate product performance and number.

 

On the real line with x>1, the Riemann zeta function can be defined by the integral

 

 

where Gamma(x) is the gamma function. If x is an integer n, then we have the identity

 

 

=

 

So,

 

 

 

To evaluate zeta(n), let y=ku so that dy=kdu and plug in the above identity to obtain

 

 =

 

 

Integrating the final expression in gives Gamma(n), which cancels the factor 1/Gamma(n) and gives the most common form of the Riemann zeta function,

 

 

 

which is sometimes known as the p-series.

 

 

 

The Riemann zeta function can also be defined in terms of multiple integrals by,

 

and as a Mellin transform by,

 

 

or 0<R[s]<1, where frac(x) is the fractional part.

 

 

 

The Riemann zeta function can also be defined in the complex plane by the contour integral

 

 

for all z!=1, where the contour is illustrated above.

 

 

 

The Riemann zeta function is related to the Dirichlet lambda function lambda(nu) and Dirichlet eta function eta(nu) by

 

 

and

 

 

 

 

 

It is also related to the Liouville function lambda(n) by

 

 

Furthermore,

 

 

where omega(n) is the number of distinct prime factors of n.

 

 

Perry


Edited by OperatorPerry - 3/21/13 at 7:19pm
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post #22 of 22
3/24/13 at 11:13am

^ LOL 

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