Asgard 2 outputs 190mw into 600 ohms.
600 ohm version of DT880 only requires 100mw, so plenty of power to spare.
Edited by ilikepooters - 3/17/13 at 9:19am
Asgard 2 outputs 190mw into 600 ohms.
600 ohm version of DT880 only requires 100mw, so plenty of power to spare.
Thanks!!
Also, keep in mind that higher impedance loads are easier on the amps themselves. Amps won't blow up under high impedance loads. In fact, true class A amps stay cooler when pushing high impedance loads. The only issue is if the volume will be load enough on some amps.
So you can actually damage an amp if you push it too hard with low impedance cans? Kinda scary, I always thought it was just speakers and headphones that would blow from too much power.


Thanks for this info. Puts me at ease. I'll be joining the schiit club soon
The best way to think of it, the amp doesn't push power into your headphones, rather your headphones suck power from the amp.
Lower impedance cans suck harder and thus put more strain on the amp.
That's my understanding of it.
If you use headphones with too low of an impedance, yes, it's technically possible to damage the amp. This is why amp manufacturers usually put a minimum impedance rating on them, usually 8, 16, or 32 ohm loads. A lot more goes into these ratings, such as damping, but you get the point. But, saying all that, it's going to be extremely rare that you damage any amp driving any headphone these days.
I could be totally wrong about this, so I'm open to being corrected, but I think you have it backwards. The amp does the pushing because that is the active device. There's nothing active about headphones that can draw current. The amp pushes into the headphones, and the resistance to being pushed is measured in ohms.
Anyone else care to chime in and set the record straight?
Current is never pushed. Current is drawn.
The amp applies a voltage across the input to the headphones, current is subsequently drawn.
The amount of current that is drawn is dependent on the voltage applied and the impedance of the headphone circuit. I=E/R, or in the case of headphones, I=E/Z, since headphones present at least some reactive impedance to the circuit.



How could I disagree? Nothing you posted in any way contradicted anything I posted, yes?

Woah I got some cables from blue jean cable (Toslink and RCA male to 1/8 plug). The backdrop for me is definitely darker.