Thanks for you detailed response.
Quote:
Originally Posted by
Pars 
. That is actually a low pass filter BTW.
One thing though. I have a problem with the statement above. If that were the case we won't hear anything, and headphones will get screwed from the DC offset. High pass means, its letting high frequencies through. I know that much as an Electrical Engineer. Here's more detailed explaination, joneeboi explain it well..
Originally Posted by joneeboi 
The capacitance you need for the diyMod refers to the high pass filter that forms when you connect your diyMod to your amplifier. When you connect a series capacitor to a parallel resistor to ground (in the amplifier, this resistor is the volume potentiometer), it forms a first order high pass filter, which allows passes mostly high frequencies while attenuating low frequencies from the signal. DC power is, all in all, 0 Hz, a low frequency. Capacitance is the amount of charge that the capacitor can hold, and in our use, you only need a small amount of capacitance in the diyMod. The equation governing the size of capacitor in a high pass filter characteristic is
C = 1/(2*pi*f*R)
where C is the capacitance in uF
f is the frequency in Hz
and R is the input impedance of the amplifier.
Basically, we want to filer out the DC while passing as much of the audio signal as necessary. Since humans can typically only hear between 20Hz and 20kHz, the highest lowest frequency you want to pass through is 20Hz, which we'll plug into the equation.
My explaination:

where f is cutoff frequency(meaning that the lower bound cutoff frequency point, since you are letting in high frequencies), and you are passing everything over 20Hz(cutoff frequency). By doing that you are filtering out DC(which has no frequency, f=0, since its not changing being constant), which is less than 20Hz, everything under 20Hz will not pass.
I guess EE school wasn't total waste of time. :)