Quote:
Originally Posted by fordgtlover
I believe you are wrong about the rotational velocidensity. Bit loss is caused by natural temperature fluctuations your harddrive is subjected to when it is turned off; specifically, nonrotational diurnal temperature variation velocidensity. If you leave your harddrive on (and spinning = no power save mode) you will not lose bits. Bit loss, or Potential errors (Pe) can be simply calculated using the following equation Here's a handy calculator to help work out your Potential errors (Pe).

Sure, if you are willing to live with the gross approximations yielded by Newtonian physics.
I admit your approximation is fine for most practical engineering applications, but this is the sound SCIENCE section.
I would transpose to account for the curvatures of space time and the increasing density and slowing clock associated with data transfer speeds as they approach the speed of light, and the gravitational effects of the speed of rotation.
The net equation comes out rather simple, as it turns out:
V = ma / ct
where V = rotational velocidensity
m = mass of drive
a = acceleration of drive
c= speed of light
t = data transfer speed
Obviously, then, as the data transfer speed approaches the speed of light, the rotational velocidensity approaches infinity. One important result is that if data transfer speed exceeds the speed of light, you will get negative rotational velocidensity, a highly volatile state of data transfer to be avoided in the presence of hydrogen. This could result in a data hole, which absorbs and scrambles data at an indefinitely increasing rate.