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# Volume pot replacement

Well, I'm replacing the burnt-out pot on my amp. I am replacing it with the cheap alps pot for radio-shack, because that's what's in there right now. But, I was wondering, because non-log pots are more linier than log pots in geneeral, wouldn't it be possible to put a resistor across the input to ground and that would make the linier pot act more like a log pot, with the added benifit of increased liniarity?

I was bored, so I drew up the following graphs. From what I see if it is correct this configuration would act just like a log pot. Here's the equations I used:
Red: y=((1/x)+.2)^-1 (pot resistance input-ground w/ 5K resisor in parallel)
Blue: y= 10-x (pot resistance input-output (10K pot)
Black y= Red(x)/Blue(x)

Anyway, sould this be a good alternative to a log pot? One potential advantage of this setup is that if I lower the value of the resistor in paralell w/ the ground the slope gets much less steap, meaning to me that the volume would raise at a lower speed, making the pot more sensitive. That was one problem that I had with my current pot, it would get too loud, too quick. Would this help?

I may try this anyway just to see how things turn out, because hey, a linier pot is only a few bucks, and if it works, it would be worth it.

Here is a fun link I've posted before on the subject:

Pots

ok,
erix