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Someone help me decode this?

post #1 of 4
Thread Starter 
I'm going to be making interconnects for my ART DI/O, and they will be attenuating using the voltage divider network Jon Risch mentions. Only thing is, I kind of sort of dont understand what he is saying

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Given the output impedance of the unit, and the very high probability that it is op-amp based, the total load it sees should be greater than 4.7 k ohms, and to get a reduction down to the industry standard of about 2 volts for 0dBFS, would require an attenuation ratio of 3.5, which equals 10.9 dB. This would be acheived using a 3.40 k ohm 1% metal film resistor in series with the output, then a 1.37 k ohm 1* metal film resistor from the output of that ressitor to ground, and the output tapped off at the junction of the two resistors.
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Does that mean the jack should look like this? : (picture)
post #2 of 4
Thread Starter 
Oops, here is the picture
post #3 of 4
Quite so.
post #4 of 4
Thread Starter 
excellent
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