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Originally Posted by VicAjax
i apologize in advance if this falls into the "duhh" category... but is it not true that the quality of digital cable matters less (still matters, of course), since the signal hasn't yet been converted to analogue?
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A digital signal is an analog signal. Depending on the coding scheme, you could have the classic square wave pattern or you could just have a high frequency analog signal. The analog signal works the same way as FM and AM radio. By controlling the frequency and amplititude of the carrier signals, you can encode a single or series of bits in one pulse. Really cool stuff and this is how they do it with stuff like wi-fi and wi-max. (They can actually transmit a unique 6 bit stream in a single pulse but I won't go into the technical stuff on how they do it).
Anyway, I think it's been pretty much covered. The operating frequencies of digital signals is much higher than audio, going up into the megahertz (VHF) for digital cable. The result being that digital cables are designed for more stringent parameters to reduce attenuation, dispersion, and induced noise. In addition, many digital interfaces use 75 Ohm cables (like digital cable) instead of 50 Ohm.
The ohmage of a cable is not its resistance, but its characteristic impedance. Impedance is a number that combines resistance, capacitance, and inductance and a perfectly loss-less cable still has a non-zero impedance. For a simple model, it represents the square root of the ratio of capacitance and inductance. So by itself, you cannot discern too much from it because you cannot determine what the absolute capacitances or inductances of the cable. What it does matter is in matching the cable and loads. Ideally, if you have a 75 ohm cable, then you want the load seen by the cable at its connections to be 75 ohms as well. If the load is not 75 ohms, then you will have a mismatch and reflections will occur. Reflections mean that part of the signal is bounced back along the cable instead of being totally transmitted (or absorbed) by the load. These reflections causes noise and jitter (delays the amount of time that it takes to tell if a digital bit is a one or a zero because of the noise).
Impedance mismatch is much more important with digital signals because of jitter (if it is applicable) and noise will create noticeable problems. With an analog signal, reflections are less important because of the large wavelength, speed of propagation, and length the cable. Simply put, the cable's signal is basically a DC signal because the wavelength is on the order of kilometers and any reflections will settle down in a very short time in comparison to the signal's frequency.